Base | Representation |
---|---|
bin | 11010101000110010100000… |
… | …001011111001111000101111 |
3 | 120100210122100022201100000011 |
4 | 122220302200023321320233 |
5 | 110323410214123102233 |
6 | 1053054552414314051 |
7 | 33450653052630604 |
oct | 3250624013717057 |
9 | 510718308640004 |
10 | 117152215440943 |
11 | 34367a80512211 |
12 | 11180a73ab8927 |
13 | 504a539155b27 |
14 | 20d02a9c646ab |
15 | d825e825d0cd |
hex | 6a8ca02f9e2f |
117152215440943 has 2 divisors, whose sum is σ = 117152215440944. Its totient is φ = 117152215440942.
The previous prime is 117152215440877. The next prime is 117152215440989. The reversal of 117152215440943 is 349044512251711.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 117152215440943 - 221 = 117152213343791 is a prime.
It is a super-2 number, since 2×1171522154409432 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (117152215440343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58576107720471 + 58576107720472.
It is an arithmetic number, because the mean of its divisors is an integer number (58576107720472).
Almost surely, 2117152215440943 is an apocalyptic number.
117152215440943 is a deficient number, since it is larger than the sum of its proper divisors (1).
117152215440943 is an equidigital number, since it uses as much as digits as its factorization.
117152215440943 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1209600, while the sum is 49.
It can be divided in two parts, 11715221 and 5440943, that added together give a square (17156164 = 41422).
The spelling of 117152215440943 in words is "one hundred seventeen trillion, one hundred fifty-two billion, two hundred fifteen million, four hundred forty thousand, nine hundred forty-three".
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