11715433 has 2 divisors, whose sum is σ = 11715434. Its totient is φ = 11715432.

The previous prime is 11715413. The next prime is 11715437. The reversal of 11715433 is 33451711.

11715433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10004569 + 1710864 = 3163^2 + 1308^2 .

It is a cyclic number.

It is not a de Polignac number, because 11715433 - 2⁵ = 11715401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11715398 and 11715407.

It is not a weakly prime, because it can be changed into another prime (11715437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5857716 + 5857717.

It is an arithmetic number, because the mean of its divisors is an integer number (5857717).

Almost surely, 2^11715433 is an apocalyptic number.

It is an amenable number.

11715433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11715433 is an equidigital number, since it uses as much as digits as its factorization.

11715433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1260, while the sum is 25.

The square root of 11715433 is about 3422.7814712599. The cubic root of 11715433 is about 227.1186413652.

The spelling of 11715433 in words is "eleven million, seven hundred fifteen thousand, four hundred thirty-three".