117167652140333 has 2 divisors, whose sum is σ = 117167652140334. Its totient is φ = 117167652140332.

The previous prime is 117167652140239. The next prime is 117167652140347. The reversal of 117167652140333 is 333041256761711.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115498395892324 + 1669256248009 = 10747018^2 + 1291997^2 .

It is an emirp because it is prime and its reverse (333041256761711) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 117167652140333 - 2¹⁰ = 117167652139309 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (117167657140333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58583826070166 + 58583826070167.

It is an arithmetic number, because the mean of its divisors is an integer number (58583826070167).

Almost surely, 2^{117167652140333} is an apocalyptic number.

It is an amenable number.

117167652140333 is a deficient number, since it is larger than the sum of its proper divisors (1).

117167652140333 is an equidigital number, since it uses as much as digits as its factorization.

117167652140333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1905120, while the sum is 50.

The spelling of 117167652140333 in words is "one hundred seventeen trillion, one hundred sixty-seven billion, six hundred fifty-two million, one hundred forty thousand, three hundred thirty-three".