Base | Representation |
---|---|
bin | 10101110101010001… |
… | …00100101100010111 |
3 | 1010020212101020111111 |
4 | 22322220210230113 |
5 | 143001102222243 |
6 | 5215024315451 |
7 | 563313661621 |
oct | 127250445427 |
9 | 33225336444 |
10 | 11721132823 |
11 | 4a75301634 |
12 | 2331472b87 |
13 | 114a45596a |
14 | 7d2989c11 |
15 | 48903839d |
hex | 2baa24b17 |
11721132823 has 2 divisors, whose sum is σ = 11721132824. Its totient is φ = 11721132822.
The previous prime is 11721132811. The next prime is 11721132901. The reversal of 11721132823 is 32823112711.
11721132823 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11721132823 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11721132323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5860566411 + 5860566412.
It is an arithmetic number, because the mean of its divisors is an integer number (5860566412).
Almost surely, 211721132823 is an apocalyptic number.
11721132823 is a deficient number, since it is larger than the sum of its proper divisors (1).
11721132823 is an equidigital number, since it uses as much as digits as its factorization.
11721132823 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4032, while the sum is 31.
The spelling of 11721132823 in words is "eleven billion, seven hundred twenty-one million, one hundred thirty-two thousand, eight hundred twenty-three".
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