Base | Representation |
---|---|
bin | 10101110110100100… |
… | …01100000110001101 |
3 | 1010021121220111020201 |
4 | 22323102030012031 |
5 | 143011400322000 |
6 | 5220054213501 |
7 | 563505466306 |
oct | 127322140615 |
9 | 33247814221 |
10 | 11732042125 |
11 | 4a80482991 |
12 | 2335054291 |
13 | 114c7a537b |
14 | 7d41c97ad |
15 | 489e9096a |
hex | 2bb48c18d |
11732042125 has 32 divisors (see below), whose sum is σ = 15571202400. Its totient is φ = 8794598400.
The previous prime is 11732042123. The next prime is 11732042137. The reversal of 11732042125 is 52124023711.
It can be written as a sum of positive squares in 16 ways, for example, as 2952726921 + 8779315204 = 54339^2 + 93698^2 .
It is not a de Polignac number, because 11732042125 - 21 = 11732042123 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11732042093 and 11732042102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11732042123) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 474571 + ... + 498679.
It is an arithmetic number, because the mean of its divisors is an integer number (486600075).
Almost surely, 211732042125 is an apocalyptic number.
It is an amenable number.
11732042125 is a deficient number, since it is larger than the sum of its proper divisors (3839160275).
11732042125 is a wasteful number, since it uses less digits than its factorization.
11732042125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24370 (or 24360 counting only the distinct ones).
The product of its (nonzero) digits is 3360, while the sum is 28.
Adding to 11732042125 its reverse (52124023711), we get a palindrome (63856065836).
The spelling of 11732042125 in words is "eleven billion, seven hundred thirty-two million, forty-two thousand, one hundred twenty-five".
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