Base | Representation |
---|---|
bin | 1010101011010001001101… |
… | …0001010111001011010011 |
3 | 1112120012001002020121221112 |
4 | 2222310103101113023103 |
5 | 3014310341022012301 |
6 | 40544324515443535 |
7 | 2321035126453343 |
oct | 252642321271323 |
9 | 45505032217845 |
10 | 11738468938451 |
11 | 3816290770422 |
12 | 1396bb15b65ab |
13 | 671c18697068 |
14 | 2c820597ad23 |
15 | 155527b159bb |
hex | aad134572d3 |
11738468938451 has 2 divisors, whose sum is σ = 11738468938452. Its totient is φ = 11738468938450.
The previous prime is 11738468938439. The next prime is 11738468938463. The reversal of 11738468938451 is 15483986483711.
11738468938451 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a balanced prime because it is at equal distance from previous prime (11738468938439) and next prime (11738468938463).
It is an emirp because it is prime and its reverse (15483986483711) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11738468938451 - 234 = 11721289069267 is a prime.
It is not a weakly prime, because it can be changed into another prime (11738468938481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5869234469225 + 5869234469226.
It is an arithmetic number, because the mean of its divisors is an integer number (5869234469226).
Almost surely, 211738468938451 is an apocalyptic number.
11738468938451 is a deficient number, since it is larger than the sum of its proper divisors (1).
11738468938451 is an equidigital number, since it uses as much as digits as its factorization.
11738468938451 is an evil number, because the sum of its binary digits is even.
The product of its digits is 139345920, while the sum is 68.
The spelling of 11738468938451 in words is "eleven trillion, seven hundred thirty-eight billion, four hundred sixty-eight million, nine hundred thirty-eight thousand, four hundred fifty-one".
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