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117414354133 is a prime number
BaseRepresentation
bin110110101011001110…
…0001101110011010101
3102020001210211012011201
41231112130031303111
53410431033313013
6125534525032501
711324431354156
oct1552634156325
9366053735151
10117414354133
114588238410a
121a9099b5731
13b0c25cbabb
14597bb9d92d
1530c2ead3dd
hex1b5670dcd5

117414354133 has 2 divisors, whose sum is σ = 117414354134. Its totient is φ = 117414354132.

The previous prime is 117414354011. The next prime is 117414354139. The reversal of 117414354133 is 331453414711.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117406966609 + 7387524 = 342647^2 + 2718^2 .

It is a cyclic number.

It is not a de Polignac number, because 117414354133 - 29 = 117414353621 is a prime.

It is a super-2 number, since 2×1174143541332 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 117414354092 and 117414354101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (117414354139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58707177066 + 58707177067.

It is an arithmetic number, because the mean of its divisors is an integer number (58707177067).

Almost surely, 2117414354133 is an apocalyptic number.

It is an amenable number.

117414354133 is a deficient number, since it is larger than the sum of its proper divisors (1).

117414354133 is an equidigital number, since it uses as much as digits as its factorization.

117414354133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 60480, while the sum is 37.

Adding to 117414354133 its reverse (331453414711), we get a palindrome (448867768844).

The spelling of 117414354133 in words is "one hundred seventeen billion, four hundred fourteen million, three hundred fifty-four thousand, one hundred thirty-three".