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117489987001613 is a prime number
BaseRepresentation
bin11010101101101101000100…
…111100001001110100001101
3120101222221012012111110011202
4122231231010330021310031
5110344423443133022423
61053514053243155245
733514241255546342
oct3255550474116415
9511887165443152
10117489987001613
1134488250783056
121121641ab15b25
135073348458b25
14210278d6127c9
15d8b2b696a728
hex6adb44f09d0d

117489987001613 has 2 divisors, whose sum is σ = 117489987001614. Its totient is φ = 117489987001612.

The previous prime is 117489987001547. The next prime is 117489987001627. The reversal of 117489987001613 is 316100789984711.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114693540183049 + 2796446818564 = 10709507^2 + 1672258^2 .

It is a cyclic number.

It is not a de Polignac number, because 117489987001613 - 214 = 117489986985229 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 117489987001613.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (117489987001633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58744993500806 + 58744993500807.

It is an arithmetic number, because the mean of its divisors is an integer number (58744993500807).

Almost surely, 2117489987001613 is an apocalyptic number.

It is an amenable number.

117489987001613 is a deficient number, since it is larger than the sum of its proper divisors (1).

117489987001613 is an equidigital number, since it uses as much as digits as its factorization.

117489987001613 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18289152, while the sum is 65.

The spelling of 117489987001613 in words is "one hundred seventeen trillion, four hundred eighty-nine billion, nine hundred eighty-seven million, one thousand, six hundred thirteen".