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11750083 is a prime number
BaseRepresentation
bin101100110100…
…101011000011
3211002222002021
4230310223003
511002000313
61055502311
7201605542
oct54645303
924088067
1011750083
1166a6014
123b27997
132585317
1417bc159
15107178d
hexb34ac3

11750083 has 2 divisors, whose sum is σ = 11750084. Its totient is φ = 11750082.

The previous prime is 11750059. The next prime is 11750099. The reversal of 11750083 is 38005711.

11750083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (38005711) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11750083 - 29 = 11749571 is a prime.

It is equal to p772711 and since 11750083 and 772711 have the same sum of digits, it is a Honaker prime.

It is not a weakly prime, because it can be changed into another prime (11753083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5875041 + 5875042.

It is an arithmetic number, because the mean of its divisors is an integer number (5875042).

Almost surely, 211750083 is an apocalyptic number.

11750083 is a deficient number, since it is larger than the sum of its proper divisors (1).

11750083 is an equidigital number, since it uses as much as digits as its factorization.

11750083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 840, while the sum is 25.

The square root of 11750083 is about 3427.8394069734. The cubic root of 11750083 is about 227.3423324888.

Adding to 11750083 its reverse (38005711), we get a palindrome (49755794).

The spelling of 11750083 in words is "eleven million, seven hundred fifty thousand, eighty-three".