117600433 has 2 divisors, whose sum is σ = 117600434. Its totient is φ = 117600432.

The previous prime is 117600421. The next prime is 117600473. The reversal of 117600433 is 334006711.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97377424 + 20223009 = 9868^2 + 4497^2 .

It is an emirp because it is prime and its reverse (334006711) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 117600433 - 2⁵ = 117600401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 117600398 and 117600407.

It is not a weakly prime, because it can be changed into another prime (117600473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58800216 + 58800217.

It is an arithmetic number, because the mean of its divisors is an integer number (58800217).

Almost surely, 2^117600433 is an apocalyptic number.

It is an amenable number.

117600433 is a deficient number, since it is larger than the sum of its proper divisors (1).

117600433 is an equidigital number, since it uses as much as digits as its factorization.

117600433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 25.

The square root of 117600433 is about 10844.3733336694. The cubic root of 117600433 is about 489.9325646473.

The spelling of 117600433 in words is "one hundred seventeen million, six hundred thousand, four hundred thirty-three".