Base | Representation |
---|---|
bin | 10101111010000100… |
… | …10110000100111010 |
3 | 1010100200020012211211 |
4 | 22331002112010322 |
5 | 143041412140010 |
6 | 5223024313334 |
7 | 564313421443 |
oct | 127502260472 |
9 | 33320205754 |
10 | 11761443130 |
11 | 4a96034338 |
12 | 2342a7284a |
13 | 11558ca808 |
14 | 7d80802ca |
15 | 48c84c08a |
hex | 2bd09613a |
11761443130 has 16 divisors (see below), whose sum is σ = 21221131680. Its totient is φ = 4693347472.
The previous prime is 11761443079. The next prime is 11761443151. The reversal of 11761443130 is 3134416711.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 11761443092 and 11761443101.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1399324 + ... + 1407703.
It is an arithmetic number, because the mean of its divisors is an integer number (1326320730).
Almost surely, 211761443130 is an apocalyptic number.
11761443130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11761443130 is a deficient number, since it is larger than the sum of its proper divisors (9459688550).
11761443130 is a wasteful number, since it uses less digits than its factorization.
11761443130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2807453.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 11761443130 its reverse (3134416711), we get a palindrome (14895859841).
The spelling of 11761443130 in words is "eleven billion, seven hundred sixty-one million, four hundred forty-three thousand, one hundred thirty".
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