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117731483971469 is a prime number
BaseRepresentation
bin11010110001001101111111…
…010001111110111110001101
3120102212000112112122121202122
4122301031333101332332031
5110412403034344041334
61054221032545302325
733540550632121634
oct3261157721767615
9512760475577678
10117731483971469
11345707074a2965
12112551979349a5
1350900539cb524
14211033ca1651b
15d926ed02332e
hex6b137f47ef8d

117731483971469 has 2 divisors, whose sum is σ = 117731483971470. Its totient is φ = 117731483971468.

The previous prime is 117731483971391. The next prime is 117731483971529. The reversal of 117731483971469 is 964179384137711.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115450447675369 + 2281036296100 = 10744787^2 + 1510310^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-117731483971469 is a prime.

It is a super-2 number, since 2×1177314839714692 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (117731483971369) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58865741985734 + 58865741985735.

It is an arithmetic number, because the mean of its divisors is an integer number (58865741985735).

Almost surely, 2117731483971469 is an apocalyptic number.

It is an amenable number.

117731483971469 is a deficient number, since it is larger than the sum of its proper divisors (1).

117731483971469 is an equidigital number, since it uses as much as digits as its factorization.

117731483971469 is an evil number, because the sum of its binary digits is even.

The product of its digits is 192036096, while the sum is 71.

The spelling of 117731483971469 in words is "one hundred seventeen trillion, seven hundred thirty-one billion, four hundred eighty-three million, nine hundred seventy-one thousand, four hundred sixty-nine".