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1177398045493 is a prime number
BaseRepresentation
bin10001001000100010011…
…001000110101100110101
311011120001220010212011021
4101020202121012230311
5123242302344423433
62300520022141141
7151031010154645
oct21104231065465
94146056125137
101177398045493
1141437155814a
121702302817b1
1387049b34627
1440db4852525
152096080522d
hex11222646b35

1177398045493 has 2 divisors, whose sum is σ = 1177398045494. Its totient is φ = 1177398045492.

The previous prime is 1177398045463. The next prime is 1177398045511. The reversal of 1177398045493 is 3945408937711.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 804783027409 + 372615018084 = 897097^2 + 610422^2 .

It is a cyclic number.

It is not a de Polignac number, because 1177398045493 - 221 = 1177395948341 is a prime.

It is a super-2 number, since 2×11773980454932 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1177398045443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 588699022746 + 588699022747.

It is an arithmetic number, because the mean of its divisors is an integer number (588699022747).

Almost surely, 21177398045493 is an apocalyptic number.

It is an amenable number.

1177398045493 is a deficient number, since it is larger than the sum of its proper divisors (1).

1177398045493 is an equidigital number, since it uses as much as digits as its factorization.

1177398045493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 22861440, while the sum is 61.

The spelling of 1177398045493 in words is "one trillion, one hundred seventy-seven billion, three hundred ninety-eight million, forty-five thousand, four hundred ninety-three".