Base | Representation |
---|---|
bin | 1010101101100000111111… |
… | …0101100001000000001011 |
3 | 1112200212122222110011002101 |
4 | 2223120033311201000023 |
5 | 3020423412344401213 |
6 | 41014150501014231 |
7 | 2323602450254506 |
oct | 253301765410013 |
9 | 45625588404071 |
10 | 11777066012683 |
11 | 3830697811584 |
12 | 13a25836b4377 |
13 | 675759bb521a |
14 | 2ca027ab413d |
15 | 15653637abdd |
hex | ab60fd6100b |
11777066012683 has 2 divisors, whose sum is σ = 11777066012684. Its totient is φ = 11777066012682.
The previous prime is 11777066012681. The next prime is 11777066012693. The reversal of 11777066012683 is 38621066077711.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11777066012683 - 21 = 11777066012681 is a prime.
Together with 11777066012681, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11777066012681) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5888533006341 + 5888533006342.
It is an arithmetic number, because the mean of its divisors is an integer number (5888533006342).
Almost surely, 211777066012683 is an apocalyptic number.
11777066012683 is a deficient number, since it is larger than the sum of its proper divisors (1).
11777066012683 is an equidigital number, since it uses as much as digits as its factorization.
11777066012683 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3556224, while the sum is 55.
The spelling of 11777066012683 in words is "eleven trillion, seven hundred seventy-seven billion, sixty-six million, twelve thousand, six hundred eighty-three".
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