11788804481 has 2 divisors, whose sum is σ = 11788804482. Its totient is φ = 11788804480.

The previous prime is 11788804427. The next prime is 11788804483. The reversal of 11788804481 is 18440888711.

11788804481 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11748608881 + 40195600 = 108391^2 + 6340^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11788804481 is a prime.

It is a super-2 number, since 2×11788804481² (a number of 21 digits) contains 22 as substring.

Together with 11788804483, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11788804483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5894402240 + 5894402241.

It is an arithmetic number, because the mean of its divisors is an integer number (5894402241).

Almost surely, 2^11788804481 is an apocalyptic number.

It is an amenable number.

11788804481 is a deficient number, since it is larger than the sum of its proper divisors (1).

11788804481 is an equidigital number, since it uses as much as digits as its factorization.

11788804481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 458752, while the sum is 50.

The spelling of 11788804481 in words is "eleven billion, seven hundred eighty-eight million, eight hundred four thousand, four hundred eighty-one".