Base | Representation |
---|---|
bin | 10101111110011100… |
… | …00111110000100111 |
3 | 1010110020011210120001 |
4 | 22333032013300213 |
5 | 143130302202042 |
6 | 5230413522131 |
7 | 565240031146 |
oct | 127716076047 |
9 | 33406153501 |
10 | 11798084647 |
11 | 5004790688 |
12 | 23531a3347 |
13 | 116038979b |
14 | 7dcc9b75d |
15 | 490b88bb7 |
hex | 2bf387c27 |
11798084647 has 2 divisors, whose sum is σ = 11798084648. Its totient is φ = 11798084646.
The previous prime is 11798084629. The next prime is 11798084659. The reversal of 11798084647 is 74648089711.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11798084647 is a prime.
It is a super-2 number, since 2×117980846472 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11798084047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5899042323 + 5899042324.
It is an arithmetic number, because the mean of its divisors is an integer number (5899042324).
Almost surely, 211798084647 is an apocalyptic number.
11798084647 is a deficient number, since it is larger than the sum of its proper divisors (1).
11798084647 is an equidigital number, since it uses as much as digits as its factorization.
11798084647 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2709504, while the sum is 55.
The spelling of 11798084647 in words is "eleven billion, seven hundred ninety-eight million, eighty-four thousand, six hundred forty-seven".
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