Base | Representation |
---|---|
bin | 110110111100011000… |
… | …1001000110011011111 |
3 | 102021112221111110000221 |
4 | 1231320301020303133 |
5 | 3413121001422111 |
6 | 130112020502211 |
7 | 11344623460603 |
oct | 1557061106337 |
9 | 367487443027 |
10 | 117990264031 |
11 | 46048478802 |
12 | 1aa4a84a967 |
13 | b184a116a3 |
14 | 59d4475503 |
15 | 310881d371 |
hex | 1b78c48cdf |
117990264031 has 2 divisors, whose sum is σ = 117990264032. Its totient is φ = 117990264030.
The previous prime is 117990264013. The next prime is 117990264127. The reversal of 117990264031 is 130462099711.
Together with previous prime (117990264013) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 117990264031 - 219 = 117989739743 is a prime.
It is a super-2 number, since 2×1179902640312 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (117990264001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58995132015 + 58995132016.
It is an arithmetic number, because the mean of its divisors is an integer number (58995132016).
Almost surely, 2117990264031 is an apocalyptic number.
117990264031 is a deficient number, since it is larger than the sum of its proper divisors (1).
117990264031 is an equidigital number, since it uses as much as digits as its factorization.
117990264031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81648, while the sum is 43.
The spelling of 117990264031 in words is "one hundred seventeen billion, nine hundred ninety million, two hundred sixty-four thousand, thirty-one".
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