Base | Representation |
---|---|
bin | 110110111101100111… |
… | …0100010100010101011 |
3 | 102021122211010202220012 |
4 | 1231323032202202223 |
5 | 3413212032313214 |
6 | 130120053122135 |
7 | 11345634263216 |
oct | 1557316424253 |
9 | 367584122805 |
10 | 118031526059 |
11 | 460697a0557 |
12 | 1aa6062934b |
13 | b19042a7a5 |
14 | 59d9b3677d |
15 | 310c26e03e |
hex | 1b7b3a28ab |
118031526059 has 2 divisors, whose sum is σ = 118031526060. Its totient is φ = 118031526058.
The previous prime is 118031526049. The next prime is 118031526061. The reversal of 118031526059 is 950625130811.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 118031526059 - 28 = 118031525803 is a prime.
It is a super-2 number, since 2×1180315260592 (a number of 23 digits) contains 22 as substring.
Together with 118031526061, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (118031526049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59015763029 + 59015763030.
It is an arithmetic number, because the mean of its divisors is an integer number (59015763030).
Almost surely, 2118031526059 is an apocalyptic number.
118031526059 is a deficient number, since it is larger than the sum of its proper divisors (1).
118031526059 is an equidigital number, since it uses as much as digits as its factorization.
118031526059 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64800, while the sum is 41.
The spelling of 118031526059 in words is "one hundred eighteen billion, thirty-one million, five hundred twenty-six thousand, fifty-nine".
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