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118035378162173 is a prime number
BaseRepresentation
bin11010110101101001000000…
…110010010100100111111101
3120110221001221110012000220002
4122311221000302110213331
5110432342423302142143
61055012412032404045
733601526464122053
oct3265510062244775
9513831843160802
10118035378162173
113467858288428a
12112a40693a6625
1350b28c4552a94
142120d2b0081d3
15d9a5875065b8
hex6b5a40c949fd

118035378162173 has 2 divisors, whose sum is σ = 118035378162174. Its totient is φ = 118035378162172.

The previous prime is 118035378162139. The next prime is 118035378162211. The reversal of 118035378162173 is 371261873530811.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 70304233796644 + 47731144365529 = 8384762^2 + 6908773^2 .

It is a cyclic number.

It is not a de Polignac number, because 118035378162173 - 212 = 118035378158077 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (118035378162113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59017689081086 + 59017689081087.

It is an arithmetic number, because the mean of its divisors is an integer number (59017689081087).

Almost surely, 2118035378162173 is an apocalyptic number.

It is an amenable number.

118035378162173 is a deficient number, since it is larger than the sum of its proper divisors (1).

118035378162173 is an equidigital number, since it uses as much as digits as its factorization.

118035378162173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5080320, while the sum is 56.

The spelling of 118035378162173 in words is "one hundred eighteen trillion, thirty-five billion, three hundred seventy-eight million, one hundred sixty-two thousand, one hundred seventy-three".