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118132107047 is a prime number
BaseRepresentation
bin110111000000100111…
…0001110011100100111
3102021220211101211001222
41232001032032130213
53413413304411142
6130134045010555
711351265225233
oct1560116163447
9367824354058
10118132107047
1146110549539
121aa8a253a5b
13b1a8215876
145a092395c3
153115edabd2
hex1b8138e727

118132107047 has 2 divisors, whose sum is σ = 118132107048. Its totient is φ = 118132107046.

The previous prime is 118132107019. The next prime is 118132107053. The reversal of 118132107047 is 740701231811.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 118132107047 - 212 = 118132102951 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 118132106998 and 118132107016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (118132707047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59066053523 + 59066053524.

It is an arithmetic number, because the mean of its divisors is an integer number (59066053524).

Almost surely, 2118132107047 is an apocalyptic number.

118132107047 is a deficient number, since it is larger than the sum of its proper divisors (1).

118132107047 is an equidigital number, since it uses as much as digits as its factorization.

118132107047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9408, while the sum is 35.

Adding to 118132107047 its reverse (740701231811), we get a palindrome (858833338858).

The spelling of 118132107047 in words is "one hundred eighteen billion, one hundred thirty-two million, one hundred seven thousand, forty-seven".