Base | Representation |
---|---|
bin | 1110000101010… |
… | …01100011111001 |
3 | 22020021212210121 |
4 | 13002221203321 |
5 | 220220310113 |
6 | 15420013241 |
7 | 2633063002 |
oct | 702514371 |
9 | 266255717 |
10 | 118135033 |
11 | 60758665 |
12 | 33691221 |
13 | 1b6230b3 |
14 | 119921a9 |
15 | a587e8d |
hex | 70a98f9 |
118135033 has 2 divisors, whose sum is σ = 118135034. Its totient is φ = 118135032.
The previous prime is 118135007. The next prime is 118135049. The reversal of 118135033 is 330531811.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 118113424 + 21609 = 10868^2 + 147^2 .
It is an emirp because it is prime and its reverse (330531811) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 118135033 - 221 = 116037881 is a prime.
It is a super-2 number, since 2×1181350332 = 27911772043822178, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 118134989 and 118135007.
It is not a weakly prime, because it can be changed into another prime (118135733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59067516 + 59067517.
It is an arithmetic number, because the mean of its divisors is an integer number (59067517).
Almost surely, 2118135033 is an apocalyptic number.
It is an amenable number.
118135033 is a deficient number, since it is larger than the sum of its proper divisors (1).
118135033 is an equidigital number, since it uses as much as digits as its factorization.
118135033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 25.
The square root of 118135033 is about 10868.9941116922. The cubic root of 118135033 is about 490.6738376094.
Adding to 118135033 its reverse (330531811), we get a palindrome (448666844).
The spelling of 118135033 in words is "one hundred eighteen million, one hundred thirty-five thousand, thirty-three".
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