Base | Representation |
---|---|
bin | 1010110000001100011100… |
… | …0001000110110111110111 |
3 | 1112212021110101201212000202 |
4 | 2230003013001012313313 |
5 | 3022202141233023441 |
6 | 41051241352231115 |
7 | 2330122110645515 |
oct | 254030701066767 |
9 | 45767411655022 |
10 | 11823088954871 |
11 | 3849164540197 |
12 | 13ab48869b49b |
13 | 679bb2a06bac |
14 | 2cc3521434b5 |
15 | 15782b9cd19b |
hex | ac0c7046df7 |
11823088954871 has 2 divisors, whose sum is σ = 11823088954872. Its totient is φ = 11823088954870.
The previous prime is 11823088954777. The next prime is 11823088954891. The reversal of 11823088954871 is 17845988032811.
11823088954871 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11823088954871 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11823088954798 and 11823088954807.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11823088954891) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5911544477435 + 5911544477436.
It is an arithmetic number, because the mean of its divisors is an integer number (5911544477436).
Almost surely, 211823088954871 is an apocalyptic number.
11823088954871 is a deficient number, since it is larger than the sum of its proper divisors (1).
11823088954871 is an equidigital number, since it uses as much as digits as its factorization.
11823088954871 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30965760, while the sum is 65.
The spelling of 11823088954871 in words is "eleven trillion, eight hundred twenty-three billion, eighty-eight million, nine hundred fifty-four thousand, eight hundred seventy-one".
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