Base | Representation |
---|---|
bin | 1010110000001110100011… |
… | …1111100000001000101011 |
3 | 1112212022221010022002020201 |
4 | 2230003220333200020223 |
5 | 3022204323143200103 |
6 | 41051414113333031 |
7 | 2330142201625354 |
oct | 254035077401053 |
9 | 45768833262221 |
10 | 11823658959403 |
11 | 3849427271015 |
12 | 13ab607567177 |
13 | 679c73b2c895 |
14 | 2cc3a7b1cd2b |
15 | 157861a7351d |
hex | ac0e8fe022b |
11823658959403 has 2 divisors, whose sum is σ = 11823658959404. Its totient is φ = 11823658959402.
The previous prime is 11823658959397. The next prime is 11823658959443. The reversal of 11823658959403 is 30495985632811.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11823658959403 is a prime.
It is a super-2 number, since 2×118236589594032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11823658959443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5911829479701 + 5911829479702.
It is an arithmetic number, because the mean of its divisors is an integer number (5911829479702).
Almost surely, 211823658959403 is an apocalyptic number.
11823658959403 is a deficient number, since it is larger than the sum of its proper divisors (1).
11823658959403 is an equidigital number, since it uses as much as digits as its factorization.
11823658959403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55987200, while the sum is 64.
The spelling of 11823658959403 in words is "eleven trillion, eight hundred twenty-three billion, six hundred fifty-eight million, nine hundred fifty-nine thousand, four hundred three".
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