Base | Representation |
---|---|
bin | 10110000001100111… |
… | …01111100010010001 |
3 | 1010112002022020000221 |
4 | 23000303233202101 |
5 | 143204112132423 |
6 | 5233204513041 |
7 | 566012332216 |
oct | 130063574221 |
9 | 33462266027 |
10 | 11824724113 |
11 | 5018826274 |
12 | 23600ab781 |
13 | 1165a55c97 |
14 | 802633b0d |
15 | 49319be5d |
hex | 2c0cef891 |
11824724113 has 2 divisors, whose sum is σ = 11824724114. Its totient is φ = 11824724112.
The previous prime is 11824724099. The next prime is 11824724117. The reversal of 11824724113 is 31142742811.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9696931729 + 2127792384 = 98473^2 + 46128^2 .
It is an emirp because it is prime and its reverse (31142742811) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11824724113 is a prime.
It is not a weakly prime, because it can be changed into another prime (11824724117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5912362056 + 5912362057.
It is an arithmetic number, because the mean of its divisors is an integer number (5912362057).
Almost surely, 211824724113 is an apocalyptic number.
It is an amenable number.
11824724113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11824724113 is an equidigital number, since it uses as much as digits as its factorization.
11824724113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10752, while the sum is 34.
The spelling of 11824724113 in words is "eleven billion, eight hundred twenty-four million, seven hundred twenty-four thousand, one hundred thirteen".
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