Base | Representation |
---|---|
bin | 10110000001101100… |
… | …00111100111010111 |
3 | 1010112010110212111222 |
4 | 23000312013213113 |
5 | 143204242101111 |
6 | 5233230120555 |
7 | 566020535261 |
oct | 130066074727 |
9 | 33463425458 |
10 | 11825347031 |
11 | 5019111283 |
12 | 236035015b |
13 | 1165c13684 |
14 | 802756b31 |
15 | 4932717db |
hex | 2c0d879d7 |
11825347031 has 2 divisors, whose sum is σ = 11825347032. Its totient is φ = 11825347030.
The previous prime is 11825347019. The next prime is 11825347097. The reversal of 11825347031 is 13074352811.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11825347031 - 210 = 11825346007 is a prime.
It is a super-2 number, since 2×118253470312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11825346982 and 11825347000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11825343031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5912673515 + 5912673516.
It is an arithmetic number, because the mean of its divisors is an integer number (5912673516).
Almost surely, 211825347031 is an apocalyptic number.
11825347031 is a deficient number, since it is larger than the sum of its proper divisors (1).
11825347031 is an equidigital number, since it uses as much as digits as its factorization.
11825347031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 35.
Adding to 11825347031 its reverse (13074352811), we get a palindrome (24899699842).
The spelling of 11825347031 in words is "eleven billion, eight hundred twenty-five million, three hundred forty-seven thousand, thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •