11843368174289 has 2 divisors, whose sum is σ = 11843368174290. Its totient is φ = 11843368174288.

The previous prime is 11843368174283. The next prime is 11843368174291. The reversal of 11843368174289 is 98247186334811.

11843368174289 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11557164573889 + 286203600400 = 3399583^2 + 534980^2 .

It is an emirp because it is prime and its reverse (98247186334811) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11843368174289 - 2¹⁶ = 11843368108753 is a prime.

It is a super-2 number, since 2×11843368174289² (a number of 27 digits) contains 22 as substring.

Together with 11843368174291, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11843368174283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5921684087144 + 5921684087145.

It is an arithmetic number, because the mean of its divisors is an integer number (5921684087145).

Almost surely, 2^{11843368174289} is an apocalyptic number.

It is an amenable number.

11843368174289 is a deficient number, since it is larger than the sum of its proper divisors (1).

11843368174289 is an equidigital number, since it uses as much as digits as its factorization.

11843368174289 is an evil number, because the sum of its binary digits is even.

The product of its digits is 55738368, while the sum is 65.

The spelling of 11843368174289 in words is "eleven trillion, eight hundred forty-three billion, three hundred sixty-eight million, one hundred seventy-four thousand, two hundred eighty-nine".