Base | Representation |
---|---|
bin | 1010110100100000111110… |
… | …1111000011000001111111 |
3 | 1120010101001220221110110011 |
4 | 2231020033233003001333 |
5 | 3024411204242320333 |
6 | 41145315510124051 |
7 | 2335360523224252 |
oct | 255101757030177 |
9 | 46111056843404 |
10 | 11897323401343 |
11 | 38776989965a6 |
12 | 1401945650627 |
13 | 683bb34cb073 |
14 | 2d1b9529b099 |
15 | 159723c249cd |
hex | ad20fbc307f |
11897323401343 has 2 divisors, whose sum is σ = 11897323401344. Its totient is φ = 11897323401342.
The previous prime is 11897323401307. The next prime is 11897323401389. The reversal of 11897323401343 is 34310432379811.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11897323401343 - 217 = 11897323270271 is a prime.
It is a super-2 number, since 2×118973234013432 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11897323401143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5948661700671 + 5948661700672.
It is an arithmetic number, because the mean of its divisors is an integer number (5948661700672).
Almost surely, 211897323401343 is an apocalyptic number.
11897323401343 is a deficient number, since it is larger than the sum of its proper divisors (1).
11897323401343 is an equidigital number, since it uses as much as digits as its factorization.
11897323401343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1306368, while the sum is 49.
The spelling of 11897323401343 in words is "eleven trillion, eight hundred ninety-seven billion, three hundred twenty-three million, four hundred one thousand, three hundred forty-three".
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