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119009751853 is a prime number
BaseRepresentation
bin110111011010110001…
…0001011001100101101
3102101011222211210102011
41232311202023030231
53422212444024403
6130401120001221
711412113125366
oct1566542131455
9371158753364
10119009751853
11465209a2023
121b094160211
13b2b7cb2b15
145a8da16b6d
15316809da6d
hex1bb588b32d

119009751853 has 2 divisors, whose sum is σ = 119009751854. Its totient is φ = 119009751852.

The previous prime is 119009751827. The next prime is 119009751857. The reversal of 119009751853 is 358157900911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 63767360484 + 55242391369 = 252522^2 + 235037^2 .

It is a cyclic number.

It is not a de Polignac number, because 119009751853 - 217 = 119009620781 is a prime.

It is a super-2 number, since 2×1190097518532 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 119009751797 and 119009751806.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (119009751857) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59504875926 + 59504875927.

It is an arithmetic number, because the mean of its divisors is an integer number (59504875927).

Almost surely, 2119009751853 is an apocalyptic number.

It is an amenable number.

119009751853 is a deficient number, since it is larger than the sum of its proper divisors (1).

119009751853 is an equidigital number, since it uses as much as digits as its factorization.

119009751853 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 340200, while the sum is 49.

The spelling of 119009751853 in words is "one hundred nineteen billion, nine million, seven hundred fifty-one thousand, eight hundred fifty-three".