Base | Representation |
---|---|
bin | 1010110100101111100000… |
… | …1010110110101101110011 |
3 | 1120010202010200201212001211 |
4 | 2231023320022312231303 |
5 | 3024442201042130133 |
6 | 41151202452140551 |
7 | 2335556254265251 |
oct | 255137012665563 |
9 | 46122120655054 |
10 | 11901223005043 |
11 | 387930a138579 |
12 | 1402653607757 |
13 | 68438539a788 |
14 | 2d20451595d1 |
15 | 1598a1267bcd |
hex | ad2f82b6b73 |
11901223005043 has 2 divisors, whose sum is σ = 11901223005044. Its totient is φ = 11901223005042.
The previous prime is 11901223005037. The next prime is 11901223005047. The reversal of 11901223005043 is 34050032210911.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11901223005043 - 25 = 11901223005011 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11901223004996 and 11901223005014.
It is not a weakly prime, because it can be changed into another prime (11901223005047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5950611502521 + 5950611502522.
It is an arithmetic number, because the mean of its divisors is an integer number (5950611502522).
Almost surely, 211901223005043 is an apocalyptic number.
11901223005043 is a deficient number, since it is larger than the sum of its proper divisors (1).
11901223005043 is an equidigital number, since it uses as much as digits as its factorization.
11901223005043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 31.
Adding to 11901223005043 its reverse (34050032210911), we get a palindrome (45951255215954).
The spelling of 11901223005043 in words is "eleven trillion, nine hundred one billion, two hundred twenty-three million, five thousand, forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •