Base | Representation |
---|---|
bin | 11011000101011101100100… |
… | …111100000000001010110101 |
3 | 120121210000021121100100211211 |
4 | 123011131210330000022311 |
5 | 111103201102004433433 |
6 | 1101204101110201421 |
7 | 34043216234163463 |
oct | 3305354474001265 |
9 | 517700247310754 |
10 | 119122611405493 |
11 | 34a57685688aa3 |
12 | 1143a915653271 |
13 | 51612a2382957 |
14 | 215b7caadd833 |
15 | db89bc2798cd |
hex | 6c5764f002b5 |
119122611405493 has 2 divisors, whose sum is σ = 119122611405494. Its totient is φ = 119122611405492.
The previous prime is 119122611405487. The next prime is 119122611405541. The reversal of 119122611405493 is 394504116221911.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 94752177169329 + 24370434236164 = 9734073^2 + 4936642^2 .
It is a cyclic number.
It is not a de Polignac number, because 119122611405493 - 213 = 119122611397301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (119122611495493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59561305702746 + 59561305702747.
It is an arithmetic number, because the mean of its divisors is an integer number (59561305702747).
Almost surely, 2119122611405493 is an apocalyptic number.
It is an amenable number.
119122611405493 is a deficient number, since it is larger than the sum of its proper divisors (1).
119122611405493 is an equidigital number, since it uses as much as digits as its factorization.
119122611405493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 466560, while the sum is 49.
The spelling of 119122611405493 in words is "one hundred nineteen trillion, one hundred twenty-two billion, six hundred eleven million, four hundred five thousand, four hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.147 sec. • engine limits •