11919100933 has 2 divisors, whose sum is σ = 11919100934. Its totient is φ = 11919100932.

The previous prime is 11919100903. The next prime is 11919100951. The reversal of 11919100933 is 33900191911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11616097284 + 303003649 = 107778^2 + 17407^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11919100933 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11919100892 and 11919100901.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11919100903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5959550466 + 5959550467.

It is an arithmetic number, because the mean of its divisors is an integer number (5959550467).

Almost surely, 2^11919100933 is an apocalyptic number.

It is an amenable number.

11919100933 is a deficient number, since it is larger than the sum of its proper divisors (1).

11919100933 is an equidigital number, since it uses as much as digits as its factorization.

11919100933 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6561, while the sum is 37.

The spelling of 11919100933 in words is "eleven billion, nine hundred nineteen million, one hundred thousand, nine hundred thirty-three".