Base | Representation |
---|---|
bin | 11011000110101010001100… |
… | …110010100111110110111011 |
3 | 120122001212122100112020011201 |
4 | 123012222030302213312323 |
5 | 111111023100402221013 |
6 | 1101305545022235031 |
7 | 34052161106210632 |
oct | 3306521462476673 |
9 | 518055570466151 |
10 | 119204884413883 |
11 | 34a8956464aa04 |
12 | 11452856725a77 |
13 | 5168c8439c038 |
14 | 21617936bc519 |
15 | dbabd50873dd |
hex | 6c6a8cca7dbb |
119204884413883 has 2 divisors, whose sum is σ = 119204884413884. Its totient is φ = 119204884413882.
The previous prime is 119204884413863. The next prime is 119204884413991. The reversal of 119204884413883 is 388314488402911.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 119204884413883 - 217 = 119204884282811 is a prime.
It is not a weakly prime, because it can be changed into another prime (119204884413863) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59602442206941 + 59602442206942.
It is an arithmetic number, because the mean of its divisors is an integer number (59602442206942).
Almost surely, 2119204884413883 is an apocalyptic number.
119204884413883 is a deficient number, since it is larger than the sum of its proper divisors (1).
119204884413883 is an equidigital number, since it uses as much as digits as its factorization.
119204884413883 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 42467328, while the sum is 64.
The spelling of 119204884413883 in words is "one hundred nineteen trillion, two hundred four billion, eight hundred eighty-four million, four hundred thirteen thousand, eight hundred eighty-three".
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