11931402544351 has 2 divisors, whose sum is σ = 11931402544352. Its totient is φ = 11931402544350.

The previous prime is 11931402544337. The next prime is 11931402544409. The reversal of 11931402544351 is 15344520413911.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11931402544351 - 2¹¹ = 11931402542303 is a prime.

It is a super-2 number, since 2×11931402544351² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11931402544298 and 11931402544307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11931402544331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5965701272175 + 5965701272176.

It is an arithmetic number, because the mean of its divisors is an integer number (5965701272176).

Almost surely, 2^{11931402544351} is an apocalyptic number.

11931402544351 is a deficient number, since it is larger than the sum of its proper divisors (1).

11931402544351 is an equidigital number, since it uses as much as digits as its factorization.

11931402544351 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 259200, while the sum is 43.

The spelling of 11931402544351 in words is "eleven trillion, nine hundred thirty-one billion, four hundred two million, five hundred forty-four thousand, three hundred fifty-one".