Base | Representation |
---|---|
bin | 10110001110100001… |
… | …10010011000011111 |
3 | 1010210122001021100011 |
4 | 23013100302120133 |
5 | 143414322014442 |
6 | 5252033344051 |
7 | 601465560046 |
oct | 130720623037 |
9 | 33718037304 |
10 | 11933001247 |
11 | 5073960502 |
12 | 2390408027 |
13 | 11823070ab |
14 | 812b7b55d |
15 | 49c939117 |
hex | 2c743261f |
11933001247 has 2 divisors, whose sum is σ = 11933001248. Its totient is φ = 11933001246.
The previous prime is 11933001211. The next prime is 11933001257. The reversal of 11933001247 is 74210033911.
11933001247 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11933001247 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11933001257) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5966500623 + 5966500624.
It is an arithmetic number, because the mean of its divisors is an integer number (5966500624).
Almost surely, 211933001247 is an apocalyptic number.
11933001247 is a deficient number, since it is larger than the sum of its proper divisors (1).
11933001247 is an equidigital number, since it uses as much as digits as its factorization.
11933001247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4536, while the sum is 31.
The spelling of 11933001247 in words is "eleven billion, nine hundred thirty-three million, one thousand, two hundred forty-seven".
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