11941433370050 has 18 divisors (see below), whose sum is σ = 22211111517579. Its totient is φ = 4776563574000.

The previous prime is 11941433370047. The next prime is 11941433370067. The reversal of 11941433370050 is 5007333414911.

11941433370050 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 5 ways, for example, as 11597614147729 + 343819222321 = 3405527^2 + 586361^2 .

It is an ABA number since it can be written as A⋅B^A, here for A=2, B=2443505.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 8 ways as a sum of consecutive naturals, for example, 24190700 + ... + 24679400.

Almost surely, 2^{11941433370050} is an apocalyptic number.

11941433370050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11941433370050 is a deficient number, since it is larger than the sum of its proper divisors (10269678147529).

11941433370050 is an frugal number, since it uses more digits than its factorization.

11941433370050 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 977414 (or 488708 counting only the distinct ones).

The product of its (nonzero) digits is 136080, while the sum is 41.

Adding to 11941433370050 its reverse (5007333414911), we get a palindrome (16948766784961).

The spelling of 11941433370050 in words is "eleven trillion, nine hundred forty-one billion, four hundred thirty-three million, three hundred seventy thousand, fifty".