1194163442653 has 2 divisors, whose sum is σ = 1194163442654. Its totient is φ = 1194163442652.

The previous prime is 1194163442639. The next prime is 1194163442677. The reversal of 1194163442653 is 3562443614911.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1176849619929 + 17313822724 = 1084827^2 + 131582^2 .

It is an emirp because it is prime and its reverse (3562443614911) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1194163442653 - 2³³ = 1185573508061 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1194163442597 and 1194163442606.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1194163442753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 597081721326 + 597081721327.

It is an arithmetic number, because the mean of its divisors is an integer number (597081721327).

Almost surely, 2^{1194163442653} is an apocalyptic number.

It is an amenable number.

1194163442653 is a deficient number, since it is larger than the sum of its proper divisors (1).

1194163442653 is an equidigital number, since it uses as much as digits as its factorization.

1194163442653 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1866240, while the sum is 49.

The spelling of 1194163442653 in words is "one trillion, one hundred ninety-four billion, one hundred sixty-three million, four hundred forty-two thousand, six hundred fifty-three".