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11943452077 is a prime number
BaseRepresentation
bin10110001111110001…
…01001110110101101
31010211100201020011221
423013320221312231
5143430010431302
65253045343341
7601653444664
oct130770516655
933740636157
1011943452077
115079849357
122393a07b51
131184525c0b
148142dbddb
1549d800937
hex2c7e29dad

11943452077 has 2 divisors, whose sum is σ = 11943452078. Its totient is φ = 11943452076.

The previous prime is 11943452071. The next prime is 11943452089. The reversal of 11943452077 is 77025434911.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9133816041 + 2809636036 = 95571^2 + 53006^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11943452077 is a prime.

It is a super-2 number, since 2×119434520772 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11943452071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5971726038 + 5971726039.

It is an arithmetic number, because the mean of its divisors is an integer number (5971726039).

Almost surely, 211943452077 is an apocalyptic number.

It is an amenable number.

11943452077 is a deficient number, since it is larger than the sum of its proper divisors (1).

11943452077 is an equidigital number, since it uses as much as digits as its factorization.

11943452077 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 211680, while the sum is 43.

Adding to 11943452077 its reverse (77025434911), we get a palindrome (88968886988).

The spelling of 11943452077 in words is "eleven billion, nine hundred forty-three million, four hundred fifty-two thousand, seventy-seven".