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119529982445437 is a prime number
BaseRepresentation
bin11011001011011000111110…
…001001001100011101111101
3120200012221202222211100202001
4123023120332021030131331
5111131334401001223222
61102115152121302301
734114520251661044
oct3313307611143575
9520187688740661
10119529982445437
11350a4420a4a843
12114a5865334991
135190823b38995
1421733d3c0555b
15dc43b0d2ee27
hex6cb63e24c77d

119529982445437 has 2 divisors, whose sum is σ = 119529982445438. Its totient is φ = 119529982445436.

The previous prime is 119529982445299. The next prime is 119529982445491. The reversal of 119529982445437 is 734544289925911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115821203624676 + 3708778820761 = 10762026^2 + 1925819^2 .

It is a cyclic number.

It is not a de Polignac number, because 119529982445437 - 215 = 119529982412669 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 119529982445437.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (119529982445537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59764991222718 + 59764991222719.

It is an arithmetic number, because the mean of its divisors is an integer number (59764991222719).

Almost surely, 2119529982445437 is an apocalyptic number.

It is an amenable number.

119529982445437 is a deficient number, since it is larger than the sum of its proper divisors (1).

119529982445437 is an equidigital number, since it uses as much as digits as its factorization.

119529982445437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 783820800, while the sum is 73.

The spelling of 119529982445437 in words is "one hundred nineteen trillion, five hundred twenty-nine billion, nine hundred eighty-two million, four hundred forty-five thousand, four hundred thirty-seven".