Base | Representation |
---|---|
bin | 10110010001000001… |
… | …10011011001101101 |
3 | 1010212002111221120201 |
4 | 23020200303121231 |
5 | 143440204230231 |
6 | 5254103113501 |
7 | 602142061504 |
oct | 131040633155 |
9 | 33762457521 |
10 | 11953976941 |
11 | 5084787895 |
12 | 2397442891 |
13 | 118676c64a |
14 | 81587b83b |
15 | 49e6ce161 |
hex | 2c883366d |
11953976941 has 2 divisors, whose sum is σ = 11953976942. Its totient is φ = 11953976940.
The previous prime is 11953976911. The next prime is 11953977029. The reversal of 11953976941 is 14967935911.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8841452841 + 3112524100 = 94029^2 + 55790^2 .
It is a cyclic number.
It is not a de Polignac number, because 11953976941 - 29 = 11953976429 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11953976911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5976988470 + 5976988471.
It is an arithmetic number, because the mean of its divisors is an integer number (5976988471).
Almost surely, 211953976941 is an apocalyptic number.
It is an amenable number.
11953976941 is a deficient number, since it is larger than the sum of its proper divisors (1).
11953976941 is an equidigital number, since it uses as much as digits as its factorization.
11953976941 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1837080, while the sum is 55.
The spelling of 11953976941 in words is "eleven billion, nine hundred fifty-three million, nine hundred seventy-six thousand, nine hundred forty-one".
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