Base | Representation |
---|---|
bin | 10110010001000111… |
… | …00001011111001001 |
3 | 1010212010212011201001 |
4 | 23020203201133021 |
5 | 143440400034433 |
6 | 5254130255001 |
7 | 602151121411 |
oct | 131043413711 |
9 | 33763764631 |
10 | 11954689993 |
11 | 5085124594 |
12 | 2397727461 |
13 | 118695c07c |
14 | 8159c5641 |
15 | 49e7c057d |
hex | 2c88e17c9 |
11954689993 has 2 divisors, whose sum is σ = 11954689994. Its totient is φ = 11954689992.
The previous prime is 11954689949. The next prime is 11954690023. The reversal of 11954689993 is 39998645911.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11485837584 + 468852409 = 107172^2 + 21653^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11954689993 is a prime.
It is a super-2 number, since 2×119546899932 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11954689193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5977344996 + 5977344997.
It is an arithmetic number, because the mean of its divisors is an integer number (5977344997).
Almost surely, 211954689993 is an apocalyptic number.
It is an amenable number.
11954689993 is a deficient number, since it is larger than the sum of its proper divisors (1).
11954689993 is an equidigital number, since it uses as much as digits as its factorization.
11954689993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 18895680, while the sum is 64.
The spelling of 11954689993 in words is "eleven billion, nine hundred fifty-four million, six hundred eighty-nine thousand, nine hundred ninety-three".
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