Base | Representation |
---|---|
bin | 1010110111110111110010… |
… | …1101111110011111010110 |
3 | 1120022212220120001220111011 |
4 | 2231331330231332133112 |
5 | 3031332303010140430 |
6 | 41232013412402434 |
7 | 2342501464562026 |
oct | 255757455763726 |
9 | 46285816056434 |
10 | 11954986411990 |
11 | 389a0991889a6 |
12 | 1410b5891641a |
13 | 689472a319cb |
14 | 2d48a5613a86 |
15 | 15ae9b1eb22a |
hex | adf7cb7e7d6 |
11954986411990 has 16 divisors (see below), whose sum is σ = 21520352684880. Its totient is φ = 4781688532960.
The previous prime is 11954986411969. The next prime is 11954986412041. The reversal of 11954986411990 is 9911468945911.
It is a super-2 number, since 2×119549864119902 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38089876 + ... + 38402455.
It is an arithmetic number, because the mean of its divisors is an integer number (1345022042805).
Almost surely, 211954986411990 is an apocalyptic number.
11954986411990 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11954986411990 is a deficient number, since it is larger than the sum of its proper divisors (9565366272890).
11954986411990 is a wasteful number, since it uses less digits than its factorization.
11954986411990 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 76507967.
The product of its (nonzero) digits is 25194240, while the sum is 67.
The spelling of 11954986411990 in words is "eleven trillion, nine hundred fifty-four billion, nine hundred eighty-six million, four hundred eleven thousand, nine hundred ninety".
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