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119550848524823 is a prime number
BaseRepresentation
bin11011001011101100011001…
…110110111110001000010111
3120200021221122012001000120002
4123023230121312332020113
5111132210114210243243
61102132522430001515
734116156321505532
oct3313543166761027
9520257565030502
10119550848524823
1135102259343051
12114a990934629b
13519279aa91611
142174413137a19
15dc4bd2b26eb8
hex6cbb19dbe217

119550848524823 has 2 divisors, whose sum is σ = 119550848524824. Its totient is φ = 119550848524822.

The previous prime is 119550848524769. The next prime is 119550848524831. The reversal of 119550848524823 is 328425848055911.

It is a strong prime.

It is an emirp because it is prime and its reverse (328425848055911) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 119550848524823 - 238 = 119275970617879 is a prime.

It is a Sophie Germain prime.

It is a self number, because there is not a number n which added to its sum of digits gives 119550848524823.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (119550848524123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59775424262411 + 59775424262412.

It is an arithmetic number, because the mean of its divisors is an integer number (59775424262412).

Almost surely, 2119550848524823 is an apocalyptic number.

119550848524823 is a deficient number, since it is larger than the sum of its proper divisors (1).

119550848524823 is an equidigital number, since it uses as much as digits as its factorization.

119550848524823 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 110592000, while the sum is 65.

The spelling of 119550848524823 in words is "one hundred nineteen trillion, five hundred fifty billion, eight hundred forty-eight million, five hundred twenty-four thousand, eight hundred twenty-three".