Base | Representation |
---|---|
bin | 10110010001010011… |
… | …10011011000010111 |
3 | 1010212020221210210212 |
4 | 23020221303120113 |
5 | 143441310224101 |
6 | 5254225440035 |
7 | 602201115614 |
oct | 131051633027 |
9 | 33766853725 |
10 | 11956336151 |
11 | 5086049351 |
12 | 23981a001b |
13 | 11870b7426 |
14 | 815cd350b |
15 | 49e9e81bb |
hex | 2c8a73617 |
11956336151 has 2 divisors, whose sum is σ = 11956336152. Its totient is φ = 11956336150.
The previous prime is 11956336127. The next prime is 11956336219. The reversal of 11956336151 is 15163365911.
11956336151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11956336151 - 26 = 11956336087 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11956336099 and 11956336108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11956330151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5978168075 + 5978168076.
It is an arithmetic number, because the mean of its divisors is an integer number (5978168076).
Almost surely, 211956336151 is an apocalyptic number.
11956336151 is a deficient number, since it is larger than the sum of its proper divisors (1).
11956336151 is an equidigital number, since it uses as much as digits as its factorization.
11956336151 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 72900, while the sum is 41.
The spelling of 11956336151 in words is "eleven billion, nine hundred fifty-six million, three hundred thirty-six thousand, one hundred fifty-one".
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