11961043 has 2 divisors, whose sum is σ = 11961044. Its totient is φ = 11961042.

The previous prime is 11961029. The next prime is 11961049. The reversal of 11961043 is 34016911.

11961043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11961043 - 2¹³ = 11952851 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11960999 and 11961017.

It is not a weakly prime, because it can be changed into another prime (11961049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5980521 + 5980522.

It is an arithmetic number, because the mean of its divisors is an integer number (5980522).

Almost surely, 2^11961043 is an apocalyptic number.

11961043 is a deficient number, since it is larger than the sum of its proper divisors (1).

11961043 is an equidigital number, since it uses as much as digits as its factorization.

11961043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 25.

The square root of 11961043 is about 3458.4740854891. The cubic root of 11961043 is about 228.6948319687.

Adding to 11961043 its reverse (34016911), we get a palindrome (45977954).

The spelling of 11961043 in words is "eleven million, nine hundred sixty-one thousand, forty-three".