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11968280342489 is a prime number
BaseRepresentation
bin1010111000101001010100…
…0110010010111111011001
31120101011020000221112210102
42232022111012102333121
53032042014231424424
641242052503425145
72343452100246632
oct256122506227731
946334200845712
1011968280342489
1138a47a0271719
121413648a551b5
1368a7b0c87983
142d53a7012889
1515b4c835d7ae
hexae295192fd9

11968280342489 has 2 divisors, whose sum is σ = 11968280342490. Its totient is φ = 11968280342488.

The previous prime is 11968280342467. The next prime is 11968280342497. The reversal of 11968280342489 is 98424308286911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9875651928025 + 2092628414464 = 3142555^2 + 1446592^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11968280342489 is a prime.

It is not a weakly prime, because it can be changed into another prime (11968280348489) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5984140171244 + 5984140171245.

It is an arithmetic number, because the mean of its divisors is an integer number (5984140171245).

Almost surely, 211968280342489 is an apocalyptic number.

It is an amenable number.

11968280342489 is a deficient number, since it is larger than the sum of its proper divisors (1).

11968280342489 is an equidigital number, since it uses as much as digits as its factorization.

11968280342489 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 47775744, while the sum is 65.

The spelling of 11968280342489 in words is "eleven trillion, nine hundred sixty-eight billion, two hundred eighty million, three hundred forty-two thousand, four hundred eighty-nine".