11968280342490 has 64 divisors (see below), whose sum is σ = 30731322176640. Its totient is φ = 2973998903040.

The previous prime is 11968280342489. The next prime is 11968280342497. The reversal of 11968280342490 is 9424308286911.

It is a Harshad number since it is a multiple of its sum of digits (57).

It is a self number, because there is not a number n which added to its sum of digits gives 11968280342490.

It is not an unprimeable number, because it can be changed into a prime (11968280342497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 172071649 + ... + 172141188.

It is an arithmetic number, because the mean of its divisors is an integer number (480176909010).

Almost surely, 2^{11968280342490} is an apocalyptic number.

11968280342490 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11968280342490 is an abundant number, since it is smaller than the sum of its proper divisors (18763041834150).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11968280342490 is a wasteful number, since it uses less digits than its factorization.

11968280342490 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 344212927.

The product of its (nonzero) digits is 5971968, while the sum is 57.

The spelling of 11968280342490 in words is "eleven trillion, nine hundred sixty-eight billion, two hundred eighty million, three hundred forty-two thousand, four hundred ninety".