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119687926481 is a prime number
BaseRepresentation
bin110111101110111110…
…1001101001011010001
3102102221020221122002222
41233131331031023101
53430110102121411
6130552303350425
711434656406034
oct1573575151321
9372836848088
10119687926481
1146839794722
121b2432b2415
13b39564cc96
145b15b0d01b
1531a78ae4db
hex1bddf4d2d1

119687926481 has 2 divisors, whose sum is σ = 119687926482. Its totient is φ = 119687926480.

The previous prime is 119687926427. The next prime is 119687926483. The reversal of 119687926481 is 184629786911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 119467700881 + 220225600 = 345641^2 + 14840^2 .

It is a cyclic number.

It is not a de Polignac number, because 119687926481 - 218 = 119687664337 is a prime.

It is a super-2 number, since 2×1196879264812 (a number of 23 digits) contains 22 as substring.

Together with 119687926483, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (119687926483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59843963240 + 59843963241.

It is an arithmetic number, because the mean of its divisors is an integer number (59843963241).

Almost surely, 2119687926481 is an apocalyptic number.

It is an amenable number.

119687926481 is a deficient number, since it is larger than the sum of its proper divisors (1).

119687926481 is an equidigital number, since it uses as much as digits as its factorization.

119687926481 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10450944, while the sum is 62.

The spelling of 119687926481 in words is "one hundred nineteen billion, six hundred eighty-seven million, nine hundred twenty-six thousand, four hundred eighty-one".