Base | Representation |
---|---|
bin | 10110010010111110… |
… | …01110010000001011 |
3 | 1010220020022021021102 |
4 | 23021133032100023 |
5 | 144003401333401 |
6 | 5255445532015 |
7 | 602431132001 |
oct | 131137162013 |
9 | 33806267242 |
10 | 11970339851 |
11 | 5092a43558 |
12 | 23a0a1400b |
13 | 1189c7b442 |
14 | 817adaa71 |
15 | 4a0d6256b |
hex | 2c97ce40b |
11970339851 has 2 divisors, whose sum is σ = 11970339852. Its totient is φ = 11970339850.
The previous prime is 11970339839. The next prime is 11970339881. The reversal of 11970339851 is 15893307911.
11970339851 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11970339851 - 214 = 11970323467 is a prime.
It is a super-2 number, since 2×119703398512 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11970339796 and 11970339805.
It is not a weakly prime, because it can be changed into another prime (11970339881) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5985169925 + 5985169926.
It is an arithmetic number, because the mean of its divisors is an integer number (5985169926).
Almost surely, 211970339851 is an apocalyptic number.
11970339851 is a deficient number, since it is larger than the sum of its proper divisors (1).
11970339851 is an equidigital number, since it uses as much as digits as its factorization.
11970339851 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 204120, while the sum is 47.
The spelling of 11970339851 in words is "eleven billion, nine hundred seventy million, three hundred thirty-nine thousand, eight hundred fifty-one".
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