Base | Representation |
---|---|
bin | 1010111000111010101100… |
… | …1001111010001000101111 |
3 | 1120101121021010222202100002 |
4 | 2232032223021322020233 |
5 | 3032131043002332221 |
6 | 41244143431054515 |
7 | 2344005514225253 |
oct | 256165311721057 |
9 | 46347233882302 |
10 | 11972945355311 |
11 | 38a6774578916 |
12 | 141452b21143b |
13 | 68b0755b87a5 |
14 | 2d56ca7d4263 |
15 | 15b69cb9480b |
hex | ae3ab27a22f |
11972945355311 has 2 divisors, whose sum is σ = 11972945355312. Its totient is φ = 11972945355310.
The previous prime is 11972945355211. The next prime is 11972945355347. The reversal of 11972945355311 is 11355354927911.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11972945355311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11972945355361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5986472677655 + 5986472677656.
It is an arithmetic number, because the mean of its divisors is an integer number (5986472677656).
Almost surely, 211972945355311 is an apocalyptic number.
11972945355311 is a deficient number, since it is larger than the sum of its proper divisors (1).
11972945355311 is an equidigital number, since it uses as much as digits as its factorization.
11972945355311 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5103000, while the sum is 56.
The spelling of 11972945355311 in words is "eleven trillion, nine hundred seventy-two billion, nine hundred forty-five million, three hundred fifty-five thousand, three hundred eleven".
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