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1197849013 is a prime number
BaseRepresentation
bin100011101100101…
…1011100110110101
310002110222000221021
41013121123212311
54423122132023
6314510021141
741453356114
oct10731334665
93073860837
101197849013
11565177769
122951a77b1
131612203ca
14b512dc7b
157026335d
hex4765b9b5

1197849013 has 2 divisors, whose sum is σ = 1197849014. Its totient is φ = 1197849012.

The previous prime is 1197848983. The next prime is 1197849049. The reversal of 1197849013 is 3109487911.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1048593924 + 149255089 = 32382^2 + 12217^2 .

It is an emirp because it is prime and its reverse (3109487911) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1197849013 - 29 = 1197848501 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1197849713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 598924506 + 598924507.

It is an arithmetic number, because the mean of its divisors is an integer number (598924507).

Almost surely, 21197849013 is an apocalyptic number.

It is an amenable number.

1197849013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1197849013 is an equidigital number, since it uses as much as digits as its factorization.

1197849013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54432, while the sum is 43.

The square root of 1197849013 is about 34609.9554030340. The cubic root of 1197849013 is about 1062.0232547755.

The spelling of 1197849013 in words is "one billion, one hundred ninety-seven million, eight hundred forty-nine thousand, thirteen".